# c6h5oh + br2

To balance the equation C6H5OH + Br2 = C6H2Br3OH + HBr using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

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### Step 1: Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable vĩ đại represent the unknown coefficients.

a C6H5OH + b Br2 = c C6H2Br3OH + d HBr

### Step 2: Create a System of Equations

Create an equation for each element (C, H, O, Br) where each term represents the number of atoms of the element in each reactant or product.

C: 6a + 0b = 6c + 0d H: 6a + 0b = 3c + 1d O: 1a + 0b = 1c + 0d Br: 0a + 2b = 3c + 1d

### Step 3: Solve For All Variables

Use substitution, Gaussian elimination, or a calculator vĩ đại solve for each variable.

• 6a - 6c = 0
• 6a - 3c - 1d = 0
• 1a - 1c = 0
• 2b - 3c - 1d = 0

Use your graphing calculator's rref() function (or an online rref calculator) vĩ đại convert the following matrix into reduced row-echelon-form:

Xem thêm: c2h2 ra ch2=ch cl

[ 6 0 -6 0 0] [ 6 0 -3 -1 0] [ 1 0 -1 0 0] [ 0 2 -3 -1 0]

The resulting matrix can be used vĩ đại determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients.

Simplify the result vĩ đại get the lowest, whole integer values.

• a = 1 (C6H5OH)
• b = 3 (Br2)
• c = 1 (C6H2Br3OH)
• d = 3 (HBr)

### Step 4: Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

C6H5OH + 3 Br2 = C6H2Br3OH + 3 HBr

Reactants Products C 6 6 ✔️ 6 6 ✔️ 1 1 ✔️ 6 6 ✔️

Since there is an equal number of each element in the reactants and products of C6H5OH + 3Br2 = C6H2Br3OH + 3HBr, the equation is balanced.

Xem thêm: zn(oh)2 + hcl